Question

in a locality 65% can read Gujarati, 36% can read Hindi and 30% can read English. 18% can read Gujarati and Hindi. 17% can read Gujarati and English and 13% can read Hindi and English. 5% can read all the three languages. find the probability that a person selected at random can read, at least one of the three languages.​

Answer 1

Answer:

Answer is 0.88

step by step explaination:

=0.65+0.36+0.30−0.18−0.17−0.13+0.05

=0.88

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Answer 2

Answer:

$\huge \tt \colorbox{lime}{꧁༺ǟռֆաɛʀ༻꧂}$

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Let E1, E2, E3 be the event of person speaking Gujarati, Hindi, English

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Required probability = [P ( E1 U E2 U E3) ]

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P ( E1 U E2 U E3) = p (E1) + p(E2) + p(E3) - p(E1 ∩ E2) - p(E1 ∩ E3) - p(E2 ∩ E3) + p(E1 ∩ E2 ∩ E3)

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=> P ( E1 U E2 U E3) = 0.65 + 0.36 + 0.30 - 0.18 - 0.17 - 0.13 - 0.05

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=> P ( E1 U E2 U E3) = 0.08

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