Math, asked by devipuspa140, 8 months ago

In a <ABC, the sides AB and AC are produced to points D and E respectively. The bisectors of <DBC
and <ECB intersect at a point O. Prove that <BOC=(90 degree + <A/2)​

Answers

Answered by optimusexpo
0

Answer:

1. With centre A and rad. AB describe a circle. With  

centre B and rad. BA describe another circle cutting the first  

in C and D. AS ABC, ABD will both be equilateral AS on AB.  

2. With centres A and B and rad. equal to 2AB describe  

circles cutting at C and D. AS ACB, AEB both f1. With centre A and rad. AB describe a circle. With  

centre B and rad. BA describe another circle cutting the first  

in C and D. AS ABC, ABD will both be equilateral AS on AB.  

Answered by anilverma470
1

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