Physics, asked by neelamrajeev8789, 7 months ago

in a machine an effort of 10 kgf is applied to lift a load of 100 kgf . what is its mechanical advantage?​

Answers

Answered by bhoomikasanjeev2009
24

Answer:

Given,

Load = 100 kgf

Effort = 10 kgf

Mechanical advantage = Load/Effort

= 100 kgf/10 kgf = 10

Answered by aneesh1983
14

Answer:

Given

Load =100 kgf

Effort =10 kgf

Mechanical advantage =

Effort

Load

=

10 kgf

100 kgf

=10

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