Question

in a machine an effort of 200N is required to lift certain load when it's efficiency is 60% find ideal effort​

Answer 1

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Answer 2

Concept Introduction:-

It could take the shape of a word or a numerical representation of a quantity's arithmetic value.

Given Information:-

We have been given that in a machine an effort of $200$N is required to lift certain load when it's efficiency is $60\%$.

To Find:-

We have to find that ideal effort​.

Solution:-

According to the problem

Efficiency $= 60\%$

When $W = 6kN = 6000 N$, $P = 200$ N

$M.A. = W/P = 6000/200 = 30$

As, Efficiency $= M.A./V.R. \times 100$       (M.A $=$ Mechanical advantage)

$V.R = (M.A/Efficiency) \times 100\\ = (30/60) \times 100 = 50$

$Ideal Effort =\frac{load}{VR}\\ =\frac{200}{50}\\ =4$

Final Answer:-

The correct answer is ideal effort​ of the machine is $4$.

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