In a magic square each row, column and diagonal have the same sum. Check which of the following is a magic square? Spammers not allowed. Right answer only?
Answers
Box (i) is not a square because all the sums not equal.
Box (ii) is a magic square because all the sums are equal.
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Given that
By adding the numbers in each rows we get,
= 5 + (- 1) + (- 4) = 5 – 1 – 4 = 5 – 5 = 0
= -5 + (-2) + 7 = - 5 – 2 + 7 = -7 + 7 = 0
= 0 + 3 + (-3) = 3 – 3 = 0
By adding the numbers in each columns we get,
= 5 + (- 5) + 0 = 5 – 5 = 0
= (-1) + (-2) + 3 = -1 – 2 + 3 = -3 + 3 = 0
= -4 + 7 + (-3) = -4 + 7 – 3 = -7 + 7 = 0
By adding the numbers in diagonals we get,
= 5 + (-2) + (-3) = 5 – 2 – 3 = 5 – 5 = 0
= -4 + (-2) + 0 = - 4 – 2 = -6
Because sum of one diagonal is not equal to zero,
So, (i) is not a magic square
Now, we consider the square (ii)
By adding the numbers in each rows we get,
= 1 + (-10) + 0 = 1 – 10 + 0 = -9
= (-4) + (-3) + (-2) = -4 - 3 – 2 = -9
= (-6) + 4 + (-7) = -6 + 4 – 7 = -13 + 4 = -9
By adding the numbers in each columns we get,
= 1 + (-4) + (-6) = 1 – 4 – 6 = 1 – 10 = -9
= (-10) + (-3) + 4 = -10 – 3 + 4 = -13 + 4
= 0 + (-2) + (-7) = 0 – 2 – 7 = -9
By adding the numbers in diagonals we get,
= 1 + (-3) + (-7) = 1 – 3 – 7 = 1 – 10 = -9
= 0 + (-3) + (-6) = 0 – 3 – 6 = -9
This (ii) square is a magic square, because sum of each row, each column and diagonal is
equal to -9.