Question

In a ‘Mahila Bachat Gat’, Sharvari invested Rs.2 on first day, Rs.4 on

second day and Rs.6 on third day. If She saves like this, then what

would be her total savings in the month of February 2010​

Answer 1

Answer :-

→ 2010 ÷ 4 = Remainder ≠ 0 . so, 2010 is a simple here in which february has 28 days .

so, we have,

• First term = 2 = a .
• Common difference = 4 - 2 = 2 = d .
• n = 28 .

then,

→ S(n) = (n/2)[2a + (n - 1)d]

→ S(n) = (28/2) [2 * 2 + (28 - 1)2]

→ S(n) = 14[4 + 27*2]

→ S(n) = 14 * 58

→ S(n) = Rs.812 (Ans.)

therefore, her saving in the month of February 2010 is Rs.812 .

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Answer 2

Answer:

$\bf 812$

Step-by-step explanation:

Amount invested by Sharvari in the month of February 2010 are as follows: 2, 4, 6,...

The above sequence is an A.P

$\bf {.}^{.}. \: \: a = 2, d = 4 - 2 = 2$

Number of days in February 2010,

$\bf \: n = 28$

$\bf \: Now, S _{n} = \frac{n}{2} [2a + (n − 1)d]$

$\bf {.}^{.}. S _{28} = \frac{28}{2} [2(2) + (28 – 1)(2)]$

$\bf= 14[4 + 27(2)]$

$\bf = 14(4 + 54)$

$\bf= 14(58)$

$\bf= 812$

.•. Total savings of Sharvari in the month of February 2010 is 812.