Math, asked by parameshbandi2211, 10 months ago

in a marriage party, three different lights shine after every 10 seconds, 15 seconds and 25;seconds respectively. if all these lights change simultaneously at 6: 25 :00 hours, then the time when they will again shine simultaneously​

Answers

Answered by pkmaurya821110
2

Answer: 6 : 27 : 30 hours

Step-by-step explanation:

Answered by amitnrw
6

Light will shine again at 6 : 27 : 30 Simultaneously

Step-by-step explanation:

In a marriage party, three different lights shine after every 10 seconds, 15 seconds and 25;seconds respectively.

to find the time difference in shining all together , we need to find LCM

10 = 2 * 5

15 = 3 * 5

25 = 5 * 5

LCM = 2 * 3 * 5 * 5

= 150

Every 150 secs lights will shine together

150 Sec = 2 : 30  mins

Lights shined at 6:25:00

after 2 :30 mins

= 6 : 27 : 30

Light will shine again at 6 : 27 : 30 Simultaneously

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