Question

In a Master-chef competition a head chef gives directions to mix 4 parts of Apple juice with
7 parts of Guava juice. These juices are to be taken by weight, but by mistake they were
taken by volume. Find the error in the percentage of the weight of apple juice in the
mixture, if 117 m^3 of the apple juice weighs as much as 151 m^3 of the guava juice.​

Answer 1

Answer:

29 % extra weight of apple juice

Step-by-step explanation:

Apple juice  =  4M

Guavava Juice = 7M

Taken

Apple = 4V

Guavava = 7V

Total = 11V

117 m^3 of the apple juice weighs as much as 151 m^3 of the guava juice.​

117 m^3 of the apple juice  weighs as much as 151 m^3 of the guava juice.​

=> 1 m^3 of the apple juice  weighs as much as 151/117 m^3 of the guava juice

=> 4V of Apple juice Weights = 4 * 151/117  = 5.16V

% Error in Apple juice = (5.16 - 4)/4  * 100  =  29%

29 % extra weight of apple juice