Question

In a mathematical competition, there are 2021 participants. Gold, silver, and bronze medals are awarded to the winners as follows:

(i) the number of silver medals is at least twice the number of gold medals;

(ii) the number of bronze medals is at least twice the number of silver medals;

(iii) the number of all medals is not more than 40% of the number of participants.

The competition director wants to maximize the number of gold medals to be awarded based on the given conditions. In this case, what is the maximum number of bronze medals that can be awarded?

Answer 1

Answer:

There are three different choices for the American.

There are 16 different choices for the first non-American and 15 different choices for the other non-American.

So, there are 3 x 16 x 15 different groups.

But, order is important -- who gets the gold, who gets the silver, and who gets the bronze -- there are 6 different ways to arrange the 3 winners (3! = 6).

Thus, there are 6 x 3 x 16 x 15 different results.