Question

In a Mathematics question paper of an engineering entrance examination, the total number of questions are 50. According to the marking scheme, 5 marks are given for every correct answer and -3 marks for every incorrect answer, and 0 for questions not attempted.
a. Saurabh attempts all questions but only 45 of his answers are correct. What is his total
b. Anmol gets 30 correct and 5 incorrect answers out of 35 questions he attempts. What is his score in Mathematics?​

Answer 1

Given:

Total number of questions in the exam = $50$

Marks allotted for correct answers = $5$

Deduction for every wrong answer = $3$ marks

To determine:

The scores of Saurabh and Anmol for according to their attempted answers information.

Step-wise Solution:

a) Saurabh

Total number of questions attempted by Saurabh = $50$

Number of the correctly attempted answers = $45$

⇒The number of questions that are wrongly attempted =$50-45=5$

Now, from the give data,

Marks awarded to Saurabh for correctly answered questions are:

$=45*5\\=225$

Marks to be deducted for wrong answers are:

$=5*3\\=15$

Now, total marks acquired by Saurabh are calculated as follows:

$=225-15\\=210$

b)Anmol:

Total number of questions attempted by Anmol = $35$

Number of correctly answered questions = $30$

Number of incorrect answers = $5$

Now, from the given data,

Marks awarded to Anmol for correct answers are:

$=30*5\\=150$

Marks to be deducted for incorrect answers are:

$=5*3\\=15$

Total marks acquired by Anmol are:

$=150-15\\=135$

Final Answer:

∴ a) The final marks awarded to Saurabh in Mathematics are $210$.

  b) The final marks awarded to Anmol in Mathematics are $135$.

Answer 2

Answer:

Given:

Total number of questions in the exam = \begin{gathered}50\\\end{gathered}

50

Marks allotted for correct answers = \begin{gathered}5\\\end{gathered}

5

Deduction for every wrong answer = \begin{gathered}3\\\end{gathered}

3

marks

To determine:

The scores of Saurabh and Anmol for according to their attempted answers information.

Step-wise Solution:

a) Saurabh

Total number of questions attempted by Saurabh = \begin{gathered}50\\\end{gathered}

50

Number of the correctly attempted answers = \begin{gathered}45\\\end{gathered}

45

⇒The number of questions that are wrongly attempted =\begin{gathered}50-45=5\\\end{gathered}

50−45=5

Now, from the give data,

Marks awarded to Saurabh for correctly answered questions are:

\begin{gathered}=45*5\\=225\\\end{gathered}

=45∗5

=225

Marks to be deducted for wrong answers are:

\begin{gathered}=5*3\\=15\\\end{gathered}

=5∗3

=15

Now, total marks acquired by Saurabh are calculated as follows:

\begin{gathered}=225-15\\=210\\\end{gathered}

=225−15

=210

b)Anmol:

Total number of questions attempted by Anmol = \begin{gathered}35\\\end{gathered}

35

Number of correctly answered questions = \begin{gathered}30\\\end{gathered}

30

Number of incorrect answers = \begin{gathered}5\\\end{gathered}

5

Now, from the given data,

Marks awarded to Anmol for correct answers are:

\begin{gathered}=30*5\\=150\\\end{gathered}

=30∗5

=150

Marks to be deducted for incorrect answers are:

\begin{gathered}=5*3\\=15\\\end{gathered}

=5∗3

=15

Total marks acquired by Anmol are:

\begin{gathered}=150-15\\=135\\\end{gathered}

=150−15

=135

Final Answer:

∴ a) The final marks awarded to Saurabh in Mathematics are \begin{gathered}210\\\end{gathered}

210

.

b) The final marks awarded to Anmol in Mathematics are \begin{gathered}135\\\end{gathered}

135

.