Physics, asked by RaikaSarkar, 22 hours ago

In a measuring cylinder with water we dip a stone of 80g.
Normally volume of water is 55cm3 , when stone is dipped it becomes 80cm3. Find density of stone.


1.45 g/cm³


1 g/cm³


3.2 g/cm³


4.3 g/cm3.

Answers

Answered by hemPatel19
0

Answer:

1.45g/cm3

Explanation:

80/55gm/cm3

80cm3 is final we want initial

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