in a medium the force of attraction between 2 point charges ,distance d apart,is Fwhat distance apart they should be kept in the same medium so the force becomes 3F
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the initial situation suggests
For=kq1q2/r1^2
For force to be triple
3for=kq1q2/r2^2
Now dividing both equally
We get
r2=r1/√3
For=kq1q2/r1^2
For force to be triple
3for=kq1q2/r2^2
Now dividing both equally
We get
r2=r1/√3
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Hey mate, yours required answer is being solved in the above attachment, hopefully it helpful to you.
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