In a meeting, 70% of the members favour a certain proposal, 30% being opposite. A member is selected at random and we take X = 0, if he opposed, and x = 1, if he is in favour. Find E(X) and variance (X).
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Answer:
E(X) = 0.7
var(X) = 0.21
I hope this helps.
Step-by-step explanation:
For the random variable X, we have
P(X=0) = P(member is opposed) = 0.3
P(X=1) = P(member is in favour) = 0.7
So
E(X) = 0×P(X=0) + 1×P(X=1) = 0×0.3 + 1×0.7 = 0.7
E(X²) = 0²×P(X=0) + 1²×P(X=1) = 0×0.3 + 1×0.7 = 0.7
var(X) = E(X²) - [E(X)]² = 0.7 - 0.7² = 0.7 - 0.49 = 0.21
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