Question

In a Mendelian cross, tall plants and purple flowers were crossed with dwarf plants and white flowers. How would you denote:
a) The genotype of the plants?
b) The genotype and phenotype of F1 progeny?
c) The results obtained by self-pollinating the F1 progeny to get F2 progeny. Give the ratio obtained in F2 progeny.

Answer 1

Answer:

Genotype of the plants- One is Homozygous tall plant with purple flowers ; other is Homozygous dwarf plant with white flowers.

Genotype of F1 progeny - All heterozygous tall plants and purple flowers.

Phenotype of F1 progeny- All tall plants and purple flowers.

Genotypic ratio in F2 progeny - 9:3:3:1

Answer 2

The genotype of plants,is TT tt PP pp.The genotype of F1 is TtPp and phenotype is tall plants and purple flowers.The results obtained by self-pollinating the F1 progeny to get F2 progeny is 9:3:3:1 .

Explanation:

(a ) In mandelian cross there is a monohybrid and dihybrid cross,here we take the dihybrid cross the dominant trait  and the recessive traits.TT PP are dominant and ttpp are recessive.These are the genotypes.

(b) The gametes formed TP TP and tp tp  and genotype is TtPp TtPp in F1 generation.The phenotype is tall plants with purple flowers.

(c) The F1 is self pollinated,to get F2,4 gametes are formed and then in punnet square the fusion gives 9:3:3:1 ratio.

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