Question

In a metal oxide 32% oxygen is present what will be equivalent mass of metal ?
(1) 17
(2) 34
(3) 32
(4) 52​

Answer 1

Answer:

17 is you answer

Explanation:

Let weight of metal oxide =100g

weight of oxygen=32g

weight of metal=100-32=68mg

Equivalent weight of oxide=

(wt×of metal/wt×of oxygen)x8

=68/32x8=17