Question

In a metal oxide 32% oxygen is present what willoxygen is present what will be equivalent mass of metal ?
(1)17
(2) 34
(3) 32
(4) 52​

Answer 1

ANSWER

In 100g,we have 32g of oxygen.

And, 100−32=68g of metal

Mass of oxygen / Mass of metal

​ =

Eq.wt.ofoxygen / Eq.wt.ofmetal

​

32/68 = 8 /x

​

x= (32/68)×8

​

x=17 gram