In a meter bridge the null point is found at a distance of 33.7c.M from a of the wire. If now a resistance of 12 ohm is connected in parallel with s the null point occurs at 51.9c.M determine the values of r and s.
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Answered by
47
The value of r and s are 6.84Ω and 13.47 Ω respectively.
Explanation :
From the 1st balance point we get,
r/s = 33.7/66.3
=> r = 33.7s/66.3
After 12Ω resistance is added in parallel with s, equivalent resistance will become,
s₁ = s||12
=> s₁ = 12s/(12+s)
From the 2nd balance point,
r/s₁ = 51.9/48.1
=> r = s₁ x 51.9/48.1
=> r = 12s/(12+s) x 51.9/48.1
=> 33.7s/66.3 = 12s/(12+s) x 51.9/48.1
=> 12 + s = (12 x 51.9 x 66.3)/(33.7 x 48.1)
=> 12 + s = 25.47
=> s = 13.47 Ω
putting the value of s in the first eqn
r = s x 33.7/66.3
=> r = 13.47 x 33.7/66.3
=> r = 6.84Ω
Hence the value of r and s are 6.84Ω and 13.47 Ω respectively.
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