Question

in a meter bridge with standard resistance of 5ohm's in the left gap the ratio of balancing lengths of meter bridge wire is 2:3 the unknown resistance is

Answer 1

Answer is 7.5 ohm
$\frac{p}{q} = \frac{r}{s}$
$\frac{2}{3} = \frac{5}{s}$
Therefore
$s = 5 \times \frac{3}{2} = 7.5 \: ohm$