Question

in a metre bridge when the resistance in the lesft gap is 2 ohm and an unknown resistance in the right gap the balance point is obtained at 40 cm from the zero end on shunting the unknown resistance with 2 ohm find the shift of the balance point on the bridge wire

Answer 1

Answer:

Explanation:

Initially resistances are R and S in the left and right gap of meter bridge.

According to formula , R/S=l/100-l.

L is given 40

Therefore R/S = 2/3

s=3R/2.

After connecting resistance 10 in series with R

R+10/S=3/2 (given that l=60)

Substituting s=3R/2 we get

2R+20/3R = 3/2 

5R =40 thus R=8.

s=12.

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Answer 2

Answer:

Explanation:

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