Physics, asked by Dvnsh8949, 8 months ago

In a Michelson experiment for measuring speed of light, the distance travelled by light between two reflections from the rotating mirror is 4.8 km. The rotating mirror has a shape of a regular octagon. At what minimum angular speed of the mirror (other than zero) the image is formed at the position where a nonrotating mirror forms it?

Answers

Answered by shilpa85475
1

The angular speed is 7.8 × 103 rev/s.

Explanation:

  • Light travels a distance from the rotating mirror (D) between two reflections = 4.8 × 103 m.
  • Number of faces that the mirror has is N = 8.
  • Mirror has the angular speed, ω= ?
  • As per the Michelson experiment, the light has the speed (c), which is shown as  
  • c = ωDN2π
  • where
  • N = polygon mirror’s faces
  • ω = angular speed
  • Therefore, ω = 2πcDN rad/s
  • = 7.8 × 103 rev/s
  • So, the angular speed is 7.8 × 103 rev/s.

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