Math, asked by srihariece555, 1 month ago

. In a milk shop there are three varieties of milk, 'Pure', 'Cure' and 'Lure'. The ‘Pure' milk has 100% concentration of milk. The ratio of milk is to water in the Cure' is 2 : 5 and in the Lure it is 3 : 8 respectively. Sonali purchase 14 litres of cure and 22 litres of Lure milk and mixed them. If she wanted to make the concentration of milk in the mixture of purchased milk to 50%. How many litres of 'Pure' milk she is needed? ​

Answers

Answered by velpulaaneesh123
2

Answer:

x= 6 litres.

Step-by-step explanation:

n the given question we've 3 kinds of milk

Since she buys 14 litres of cure milk as they are in 2: 5 milk to water ratio. Hence 4 litres milk 10 litres water. When 22 litres of lure milk she's buying that has 6 litres milk 16 litres water.

When it is being mixed it has 36 litres of milk quantity with 10 litres milk and 26 litres water.

To make this ratio of 1:2 it will be 50 percent milk concentration.

Now for adding these entire milk together we fram the equation for quantities of milk as

Let x litres pure milk quantity be added

26+x= 2(10+x)\\\\26 + x = (20 + x)\\\\26 + x = 20 + x\\\\x = 26 - 20\\\\x = 6

x= 6 litres.

Similar questions