In a mixture contained 700 litre of three liquids, the ratio of first and second liquid is 2:3 and second and third is 4:5, how much amount of first and second liquids are mixed to the mixture so that the ratio of three liquids will become 6:5:3?
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Answer:
Answer:
22/13
Step-by-step explanation:
First nd = 2/3
multiplying by 4 both sides
First: Second =8:12
Second: Third =4:5
multiplying by 3 both sides
Second: Third = =12:15
as now 12 is common for second in both ratios
=> First: Second: Third l = 8/12 / 15
Let say quantities are
8A, 12A & 15A
total = 8A + 12A + 15A = 35A
=>35A=700
=>A=20
irst = 8A = 160Litre
Second = 12A = 240Li
Third = 15A = 300 Litre
Let say A & B are mixed X\&Y litre respectively
then
First = 160 + X litreSecond = 240 + Y Litre
Third 300 Litre
Total = 700 + X + Y litre
New ratio
6/5 / 3
160 + X / 24 * O + Y / 30
(160 + X) / 300 = 6/3
=>160+X=600
=>x=440
(240 + Y) / 300 = 5/3
=>24O+Y=500
=>Y=260
X / Y - 40/26
Rightarrow X:Y::22:13
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