Question

In a mixture contained 700 litre of three liquids, the ratio of first and second liquid is 2:3 and second and third is 4:5, how much amount of first and second liquids are mixed to the mixture so that the ratio of three liquids will become 6:5:3?

Answer 1

Answer:

Answer:

22/13

Step-by-step explanation:

First nd = 2/3

multiplying by 4 both sides

First: Second =8:12

Second: Third =4:5

multiplying by 3 both sides

Second: Third = =12:15

as now 12 is common for second in both ratios

=> First: Second: Third l = 8/12 / 15

Let say quantities are

8A, 12A & 15A

total = 8A + 12A + 15A = 35A

=>35A=700

=>A=20

irst = 8A = 160Litre

Second = 12A = 240Li

Third = 15A = 300 Litre

Let say A & B are mixed X\&Y litre respectively

then

First = 160 + X litreSecond = 240 + Y Litre

Third 300 Litre

Total = 700 + X + Y litre

New ratio

6/5 / 3

160 + X / 24 * O + Y / 30

(160 + X) / 300 = 6/3

=>160+X=600

=>x=440

(240 + Y) / 300 = 5/3

=>24O+Y=500

=>Y=260

X / Y - 40/26

Rightarrow X:Y::22:13