In a mixture of 126kg of milk and water, milk and water are in a ration 5:2. How much water must be added to the mixture to make this ratio 3:2
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what a question?
and which std you are?
Step-by-step explanation:
Vazish07:
I'm from icse..
10th std
i want to say that the meaning of this question i dont understood
In the original mass of 126 kg of the mixture there are 7 (= 5 + 2) equal parts (masses). Hence, the milk contents is  = 5*18 = 90 kg, and water contents is  = 2*18 = 36 kg. OK. Next, the final mixture, having 90 kg of milk, must contain  = 30*2 = 60 kg ow water to provide the ratio  = . Hence, 60 - 36 = 24 kg of water must be added to the original mixture to satisfy the problem requirements.
Answer. 24 kg of water must be added to the original mixture.
Answer. 24 kg of water must be added to the original mixture.
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