Math, asked by abhishekmishram703, 3 months ago

In a mixture of 72 Itr, the ratio of milk and water is 7:5. If some amount of the mixture is removed in which 5 ltr was water and 1 ltr of water is added afterwards into the remaining mixture, then find the new ratio of milk: water​

Answers

Answered by AmalVerma
0

Answer:

the new ration of milk and water is 37:31

Step-by-step explanation:

the ratio of milk and water is 7:5

let the common multiple be x

milk =7x

water=5x

According to given condition

5x+7x=72

12x=72

x=72÷12

x=6

milk =7x

=7×6

=42 liter

water=5x

=5×6

=30 liter

In a mixture of 72 liter milk is 42 liter and water is 30 liter

For new proportion

milk=(42-5) liter

=37liter

water=(30+1) liter

=31 liter

therefore,the new ratio of milk:water is

new proportion of milk/new propotion of water=37/31

=37:31

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