Question

In a mixture of a, b and c, if a and b are mixed in 3:5 ratio and b and c are mixed in 8:5 ratio and if the final mixture is 35 liters, find the amount of b?; In a mixture of a, b and c, if a and b are mixed in 3:5 ratio and b and c are mixed in 8:5 ratio and if the final mixture is 35 liters, find the amount of b?

Answer 1

Answer:

15.73 Litre

Step-by-step explanation:

Let say b = 40 x

a : b :: 3:5

=> a/b  = 3/5

=> a = 3b/5

=> a = 3 * 40x /5

=> a = 24x

b: c :: 8:5

=> b/c = 8/5

=> c = 5b/8

=> c = 5 * 40x /8

=> c = 25x

a + b +c = 24x + 40x + 25x =

=> a + b + c = 89x

89x  = 35 Litre

1 = 35/89x

40x = (35/89x) * 40x

=> b = 15.73 Litre

Answer 2

$\huge\bold{Answer}$

=> Let b = 20 x.

=>a:b = 3:5 .

=>$\frac{a}{b}$ = $\frac{3}{5}$

=>a = $\frac{3b}{5}$

=>a= $\frac{3 × 20 x}{5}$

=>a = 12x

=>B:c = 8:5

=>$\frac{b}{c}$ = $\frac{8}{5}$

=> c = $\frac{5b}{8}$

=>c = $\frac{5× 20x }{8}$

=> c= 12.5 .

=>a+ b+ c = 12x + 20x + 12.5x

=> a+b+ c= 44.5

=> 44.5 x = 35 l.

=> b = $\frac{44.5}{35}$

=>b = $\frac{35}{44.5}$&20 x.

=>b= $\frac{20×35}{44.5} [tex]\huge\bold{=>\:b\:=\: 15.73l}$