Math, asked by sobitadas055, 1 month ago

In a mixture of lassi, there are five parts of curd ,3 parts of water and 2 part of sugar syrup. Find Te percentage of a) curd b) water c) sugar syrup in the mixture. ​

Answers

Answered by gak13331
3

Answer:

curd =5,water =3,sugar syrup=2 total parts=5+3+2=10

percentage of curd =5/10 × 100 = 50%

percentage of water = 3/10×100= 30%

percentage of sugar syrup= 2/10 × 100= 20%

Step-by-step explanation:

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Answered by architsinghkol
2

Answer:

a)50%(Curd)

b)30%(Water)

c)20%(Sugar Syrup)

Step-by-step explanation:

5+3+2=10

=10*10=100%

=5*10=50%(Curd)

=3*10=30%(Water)

=2*10=20%(Sugar Syrup)

50%(Curd)

30%(Water)

20%(Sugar Syrup)

Hope it helped, have a great day.

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