in a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36
gms of pure milk is added, what would be the percentage of milk in the mixture formed?
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If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed? Explanation: Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%
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