Question

In a mixture of petrol and kerosene, petrol is only 99 litres. if this same quantity of petrol would be presented in another mixture of petrol and kerosene where total volume would be 198 litres less than the actual mixture then the concentration of petrol in the present mixture would have been 13.33% point less than that. what is the concentration of petrol in actual mixture?

Answer 1

Lets assume amount of petrol = x

So, (x*100)/198=13.33

x=26.3934  

Now same amount of petrol is in 99 liters also.

so the percentage in actual mixture is

(26.3934*100)/99 =26.66%

Answer 2

PETROL           kerosene                 total

99                    x                                99+x          (first mixture)

99                    x-198                         x-99            (second mixture)

as acc. to question     99+kerosene=99+x-198=x-99

now

99/x-198 *100 - 99/x-198*100  = 13.33

on solving

x =396

therefore concentration of petrol in actual mixture =99/99+396 =20%