in a mixture of petrol and kerosene, petrol is only 99 litres.if this same quantity of petrol is presented in another mixute of petrol and kerosene where total volume would be 198 litres less than the actual mixture,then the concentration of petrol in the actual mixture would have been 13.33% point less than that of the new mixture.what is the concentration of petrol in actual mixture?
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Lets assume amount of petrol = x
So, (x*100)/198=13.33
x=26.3934
Now same amount of petrol is in 99 liters also.
so the percentage in actual mixture is
(26.3934*100)/99 =26.66%
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