Question

in a mixture of three liquids, X, Y, Z the weight of each is 872g, 1010g and 905g respectively. If 1.2l of X, 1.6l of Y and 3.4l of z are mixed find the weight of the mixture in grams
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Answer 1

Answer:5758.22

Step-by-step explanation:

X = 872g  Y = 1010g  Z= 905g

1.21 of 872g = 1055.12g

1.61 of 1010g = 1626.1g   [ IN THE PLACE OF [OF] USE Multiplication symbol ]

3.41 of Z = 3077g

SO, X+Y+Z = 1055.12g + 1626.1g + 3077g = 5758.22g.

This answer is absolutely right..

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