Math, asked by shringarika7422, 9 months ago

In a mixture the ratio of alcohol and water is 6:5.When 22liters mixture are replaced by water the ratio becomes 9:13 find the quantity of water after replacement

Answers

Answered by windyyork
7

There is 52 liters of water after replacement.

Step-by-step explanation:

Since we have given that

Ratio of alcohol to water = 6:5

Quantity of mixture = 22 liters

So, the capacity of alcohol = \dfrac{6}{11}\times 22=6\times 2=12

the capacity of water = \dfrac{5}{11}\times 22=5\times 2=10\ liters

According to question, we get that

\dfrac{6x-12}{5x-10+22}=\dfrac{9}{13}\\\\\dfrac{6x-12}{5x+12}=\dfrac{9}{13}\\\\13(6x-12)=9(5x+12)\\\\78x-156=45x+108\\\\78x-45x=108+156\\\\33x=264\\\\x=\dfrac{264}{33}=8

So, the water would be

5x+12=5(8)+12=40+12=52\ liters

Hence, there is 52 liters of water after replacement.

# learn more:

Illustration 18: A mixture contains alcohol and water

in the ratio of 6:1. On adding 8 litres of water, the ratio

of alcohol to water becomes 6:5. Find the quantity of

water in the mixture.​

https://brainly.in/question/11520891

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