Question

in a mole of water vapour at stp, the volume actually occupied or taken by the molecules (i.e., avogadro’s no. volume of one molecule) is (a) zero (b) less than 1% of 22.4 litres (c) about 10% of the volume of container (d) 1% to 2% of 22.4 litres

Answer 1

the correct answer is B) less then 1% of 22.4

Answer 2

Explanation:

As density of water is 1g/cc, so 1 mol of water I. e., 18 g water should have actually occupied 18 cc volume in liquid phase. But in vapour phase it's volume is 22400cc., out of which it's actual volume of molecules is 18cc.

So percentage of volume actually occupied by the molecules is

(18 /22400)x100 = .08