In a monohybrid cross between two heterozygous individuals, percentage of pure homozygous individuals obtained in F1 generation will be
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(i.e 50%)
Reason: Let us consider a monohybrid cross between two tall heterozygous plants (Tt). The genotype of the offspring in F1 generation will be, TT, Tt,Tt, and tt. Hence half of the offspring (i.e 50%) are pure homozygous.
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25% of the individuals will have pure homozygous character.
Explanation:
- By the monohybrid cross between two heterozygous individual having the The phenotype of Tt, the number offsprings that are formed are TT,2Tt , tt.
- A phenotype is said to be pure homozygous when both the l are same for a particular character. Therefore 25% of the individuals will have the pure dominant character in their genotype. This is found out by the punnett square
to know more about monohybrid cross,
Explain mono hybrid and dihybrid cross??? - Brainly.in
https://brainly.in/question/7808535
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