In a morning walk three persons step off together their steps measuring 110cm 120cm and125cm respectively. WHat is the minimum distance each should walk so that they can cover the distance in complete steps?
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Hello mate....
In this problem we have to find the LCM of 110 cm,120 cm and 125 cm.
We are doing this because we need to the minimum distance.
Therefore,
110 = 2 × 5 × 11
125 = 5 × 5 × 5
120 = 2 × 2 × 2 × 3 × 5
∴The LCM of (110,120,125) is 33000.
Hope this helps you.........
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