Question

in a morning walk three persons step off together their steps measure 80 CM 85 cm and 90 cm respectively what is the minimum distance each would should walk so that they could can never cover the distance in complete step​

Answer 1

Answer:

Hey!

Prime factorisation of a natural number is unique.

80= 2 × 2 × 2 × 2 × 5

85 = 5 × 17

90 = 2 × 3 × 3 × 5

LCM of 80,85 and 90 =2 ×2 × 2 × 2 × 3 × 3 × 5 × 17 = 12240

Minimum distance each should walk so that they can cover the distancein complete

steps = 12240 cm = 122.4 m

Hope it will be helpful ✌️

Answer 2

$\huge{\textbf{\underline{\underline{QUESTION:}}}}$

In a morning walk three persons step off together their steps measure 80 CM 85 cm and 90 cm respectively. What is the minimum distance each would should walk so that they could can never cover the distance in complete step?

$\huge{\textbf{\underline{\underline{ANSWER:}}}}$

Prime factorisation of a natural number is unique.

80= 2 × 2 × 2 × 2 × 5

85 = 5 × 17

90 = 2 × 3 × 3 × 5

LCM of 80,85 and 90 =2 ×2 × 2 × 2 × 3 × 3 × 5 × 17 = 12240 cm

Minimum distance each should walk so that they can cover the distancein complete

steps = 12240 cm = 122.4 m

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