Question

In a morning walk three persons step off together, their steps measure 80cm, 85cm and 90cm respectively. What is the minimum distance each should walk so that he can cover the distance in complete steps?

Answer 1

Answer:

Prime factorisation of a natural number is unique.

80= 2 × 2 × 2 × 2 × 5

85 = 5 × 17

90 = 2 × 3 × 3 × 5

LCM of 80,85 and 90 =2 ×2 × 2 × 2 × 3 × 3 × 5 × 17 = 12240

Minimum distance each should walk so that they can cover the distance in complete

steps = 12240 cm = 122.4 m

Step-by-step explanation:

Answer 2

Answer:

Prime factorisation of a natural number is unique.

80= 2 × 2 × 2 × 2 × 5

85 = 5 × 17

90 = 2 × 3 × 3 × 5

LCM of 80,85 and 90 =2 ×2 × 2 × 2 × 3 × 3 × 5 × 17 = 12240

Minimum distance each should walk so that they can cover the distance in complete

steps = 12240 cm = 122.4 m