In a morning walk three persons step off together, their steps measure 80cm, 85cm and 90cm respectively. What is the minimum distance each should walk so that he can cover the distance in complete steps?
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Answer:
Prime factorisation of a natural number is unique.
80= 2 × 2 × 2 × 2 × 5
85 = 5 × 17
90 = 2 × 3 × 3 × 5
LCM of 80,85 and 90 =2 ×2 × 2 × 2 × 3 × 3 × 5 × 17 = 12240
Minimum distance each should walk so that they can cover the distance in complete
steps = 12240 cm = 122.4 m
Step-by-step explanation:
Answered by
0
Answer:
Prime factorisation of a natural number is unique.
80= 2 × 2 × 2 × 2 × 5
85 = 5 × 17
90 = 2 × 3 × 3 × 5
LCM of 80,85 and 90 =2 ×2 × 2 × 2 × 3 × 3 × 5 × 17 = 12240
Minimum distance each should walk so that they can cover the distance in complete
steps = 12240 cm = 122.4 m
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