in a morning walk, three persons step off together. their steps measure 70 cm, 75cm and 80 cm respectively. What is the minimum distance each should walk so all can cover the same distance in complete steps?
Answers
Answer:
SOLUTION :
GIVEN: Their steps measure 80 cm, 85 cm and 90 cm.
We have to find the L.C.M of the measur
es of their steps i.e. 80 cm, 85 cm, and 90 cm, to calculate the required distance each should walk.
L.C.M of 80 cm, 85 cm, and 90 cm.
80 = 2⁴ x 5
85 = 17 x 5
90 = 2 x 3 x 3 x 5
L.C.M of 80, 85 and 90 = 2⁴ x 3 x 3 x 5 x 17
L.C.M of 80, 85 and 90 = 12240 cm
Hence, the minimum distance each should walk so that all can cover the same distance in complete steps is 12240 cm.
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Answer:
Step-by-step explanation:
GIVEN: Their steps measure 70 cm, 75 cm and 80 cm.
We have to find the L.C.M of the measur
es of their steps to calculate the required distance each should walk.
L.C.M of 70 cm, 75 cm, and 80 cm.
70 = 2 x 5 X 7
75 = 3 x 5^2
80 = 2^4 x 5
L.C.M of 70, 75 and 80 = 2⁴ x 3 x 5^2 x 7
L.C.M. = 8400 cm
Hence, the minimum distance each should walk so that all can cover the same distance in complete steps is 8400 cm.