Math, asked by durgayadav1955k, 8 months ago

in a morning walk, three persons step off together. their steps measure 70 cm, 75cm and 80 cm respectively. What is the minimum distance each should walk so all can cover the same distance in complete steps?​

Answers

Answered by keya4543
33

Answer:

SOLUTION :  

GIVEN: Their steps measure 80 cm, 85 cm and 90 cm.

We have to find the L.C.M of the measur

es of their steps i.e. 80 cm, 85 cm, and 90 cm, to calculate the required distance each should walk.

L.C.M of 80 cm, 85 cm, and 90 cm.

80 = 2⁴ x 5

85 = 17 x 5

90 = 2 x 3 x 3 x 5

L.C.M of 80, 85 and 90 = 2⁴ x 3 x 3 x 5 x 17

L.C.M of 80, 85 and 90 = 12240 cm

Hence, the minimum distance each should walk so that all can cover the same distance in complete steps is 12240 cm.

HOPE THIS ANSWER WILL HELP YOU. .

Answered by rajiv2rajiv
26

Answer:

Step-by-step explanation:

GIVEN: Their steps measure 70 cm, 75 cm and 80 cm.

We have to find the L.C.M of the measur

es of their steps to calculate the required distance each should walk.

L.C.M of 70 cm, 75 cm, and 80 cm.

70 = 2 x 5 X 7

75 = 3 x 5^2

80 = 2^4 x 5

L.C.M of 70, 75 and 80 = 2⁴ x 3 x 5^2 x 7

L.C.M. = 8400 cm

Hence, the minimum distance each should walk so that all can cover the same distance in complete steps is 8400 cm.

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