Question

in a motion along x axis with constant accerlation , the velocity is reduced to 0 in 5 second after covering distance of 100m the distance covered by particle in next 5 s if it move with same accerlation will be​

Answer 1

Explanation:

V=u+at

0=u+5a

u = -5a

Now,

v^2=u^2+2aS

0=25a^2+2aS

0=25a+2S

0=25a+2×100

a = -2×100/25

a = -8 m/s^2

After stopping ,

Now,

S=ut+1/2at^2

S=0×t + 1/2 × 8 × 25

S = 100