Question

in a motion along x axis with constant accerlation , the velocity is reduced to 0 in 5 second after covering distance of 100m the distance covered by particle in next 5 s if it move with same accerlation will be​

Answer 1

A = (v-u)/t (0-u)/t

= u = 40 m/s = -(40 m/s) / (5 s) Displacement covered in 10 seconds Particle travelled 100 m in first 5 seconds

=-u/(5 s)

Sut+ 0.5at²

100 = 5u+ (0.5 × [-u / (5 s)] × (5 s)²) X X

100 = 5u-2.5u

100 = 2.5u

If u = 40 m/s then

a = -u / (5 s)

= -8 m/s²

S = ut + 0.5at²

= (40 m/s x 10 s) + [0.5 × (-8 m/s² × (10 s)²] = 0m

and in next 5 seconds it travels 100 m back to initial position. Hence we got Displacement after 10 seconds equal to zero.

Hence,in a motion along x axis with constant accerlation , the velocity is reduced to 0 in 5 second after covering distance of 100m the distance covered by particle in next 5 s if it move with same accerlation will be zero