Question

In a motion with constant acceleration the velocity
is reduced to zero in 5 seconds and after covering a
distance of 100 m. The distance covered by the
particle in next 5 seconds will be:
(a) zero (6) 250 m (c) 100 m (d) 500 m​

Answer 1

Answer:

I think The answer is 250 hope it will help you

Answer 2

Answer:

zero

Explanation:

A = (v - u)/t

   = (0 - u)/t

   = -u / (5 s)

S = ut + 0.5at²

100 = 5u + (0.5 × [-u / (5 s)] × (5 s)²)

100 = 5u - 2.5u

100 = 2.5u

u = 40 m/s

If u = 40 m/s then

a = -u / (5 s)

   = -(40 m/s) / (5 s)

   = -8 m/s²

Displacement covered in 10 seconds

S = ut + 0.5at²

   = (40 m/s × 10 s) + [0.5 × (-8 m/s² × (10 s)²]

   = 0 m