Question

In a multiplication sum of multiplicand is 999 and last 3 digit of the product is 193. other figures are missing. complete the multiplication by supplying the missing figures.

Answer 1

Given:

In a multiplication sum of multiplicand is 999 and last 3 digit of the product is 193 and other figures are missing.

To Find:

Complete the multiplication by supplying the missing figures.

Solution:

it is given that- in a multiplication sum of multiplicand is 999 and last 3 digit of the product is 193.

Let if possible, the multiplier be the 3-digit number XYZ.

We know , 999 times XYZ is a number with last 3-digits 193.

⇒ $XYZ \times999=???193$

⇒$999\times XYZ =1000\times XYZ-1 \times XYZ$

⇒$1000 \times XYZ - XYZ= ???193$

1000 times XYZ is a number that ends with 3 zeros. The 3-digit number XYZ , substracted from a number that ends with 3 zeros , equals a number with last 3-digit 193. That gives us only the possible values for XYZ;

$XYZ000-XYZ=???193\\???193+XYZ=XYZ000\\XYZ=807$

Hence, multiplier is 807.

the multiplier is any integer with last 3-digit 807 ...

Answer 2

Answer:

The multiplier is 807.

Hope it will help you.

pls mark me as brainiest..