Question

In a NaCl type crystal distance between Nat and
cr ion is 2.814 Å and the density of solid is
2.167 g cmthen find out the value of Avogadro
constant.
(1) 6.05 x 1023
(2) 3.02 x 1023
(3) 12.10 x 1023 (4) 9.6 x 1024​

Answer 1

Answer:

i think this would help

Explanation:

a=2(r++r−)=2×281=562pm

d=Z×MNA×V

2.61=4×58.5NA×(562×10−10)3

NA=6.01×1023