In a NaOH solution, [OH-] is 2.0 x 10-4 M. Calculate the pH of the solution at 25oC.
Answers
Answer:
First, we need to know how to calculate?
Calculate the pH of a 0.1 M NaOH solution. Alternatively we can calculate pOH = - log [OH-]= - log [10-1] = 1 and remembering that pH + pOH = 14 we get pH = 14 - 1 = 13.
How to find pOH?
To find the pOH, simply subtract the pH from 14. In order to calculate the pOH, take the negative log of the hydroxide ion concentration. To find the pH, simply subtract pOH from 14.
Hi, hope it is helpful...
Since NaOH is a strong base it will completely ionize. Therefore, if the molarity of the solution is 2.9x10^4 , the concentration of OH ions will be 2.9x10^-4.
The pOH of the solution is determined using the formula pOH = log 1/2.9x10^-4 which is 3.54
Now recall that the pH of a basic solution is Determined using the equation pH= 14-pOH
The pH of this NaOH solution is 24–3.54 = 10.46.
Something to remember: in chemistry, the letter “p” is a mathematical operator. Just as + says “add”, p says “take the log of the reciprocal of”
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