Question

In a neon gas discharge tube, every second 4.8*10* ne' ions move towards the right through a cross-
section of the tube, while 'n' electrons move to the left in the same time. if the current in the tube is 1.12
amperes towards the right, 'n' is equal to (given e=1.6x10 coulomb)
b) 22x10
c) 2.4x10
d) 2.8x10
a) 1.8x10'​

Answer 1

charge moving towards right due to positive ions

Q

+ve

=2.9×10

18

×1.6×10

−19

=0.464C

charge moving towards left due to electron

Q

−ve

=−1.2×10

18

×1.6×10

−19

=0.192C

total positive charge moving through a cross section area towards right will be

Q=0.464−(−0.192)=0.656=0.66C

as positive charge is moving towards right so current will have same direction

and

I=

t

Q

=

1sec

0.66C

=0.66A

This is you answer. Hope it helps you!!!

Answer 2

Answer:

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