in a network as shown in the figure the potential diffrence across the resistance 2R is
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3
Answer:
Total resistance of circuit is R
t
=R+
2R+4R
2R.4R
=
3
7R
Current in the circuit is I=
R
t
E
=3E/7R
Potential across R is V
1
=IR=3E/7
As R and (2R, 4R) are in series so potential across (2R,4R) is V
2
=E−V
1
=E−3E/7=4E/7. This is also potential across 2R because 2R and 4R are in parallel.
Explanation:
Answered by
0
Answer:
question_answer In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volts and has no internal resistance) A) 2E. B) \frac{4E}{7}
Explanation:
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