Question

in a network as shown in the figure the potential diffrence across the resistance 2R is​

Answer 1

Answer:

Total resistance of circuit is R  

t

​  

=R+  

2R+4R

2R.4R

​  

=  

3

7R

​  

 

Current in the circuit is I=  

R  

t

​  

 

E

​  

=3E/7R

Potential across R is V  

1

​  

=IR=3E/7

As R and (2R, 4R) are in series so potential across (2R,4R) is V  

2

​  

=E−V  

1

​  

=E−3E/7=4E/7. This is also potential across 2R because 2R and 4R are in parallel.

Explanation:

Answer 2

Answer:

question_answer In a network as shown in the figure, the potential difference across the resistance 2R is (the cell has an emf of E volts and has no internal resistance) A) 2E. B) \frac{4E}{7}

Explanation: