Question

In a neutral sphere, 5(10^21) electrons are present. If 10% electrons are removed, then calculate the charge on the sphere

Answer 1

IF 10% ELECTRONS ARE REMOVED THAT MEANS 5*10^19 electrons are removed
so increase in +ve charge is same as decrease in total electronic charge i.e
(1.6*10^19)*(5*10^19) coloumb

Answer 2

Answer: 10% of 5×10^21 electrons are removed = 5×10^20 .

Q=ne = 5×10^20 × 1.6×10^-19 = 8×10 columb= 80 columbs.