Question

In a neutral sphere 5 into 10 rest to the power 21 electrons are present. If 10 percent electrons are removed then calculate the charge on sphere

Answer 1

Given that,

Charge present in a neutral sphere is $5\times 10^{21}$. If 10 percent electrons are removed.

To find,

The charge on the sphere, if 10 percent electrons are removed.

Solution,

If 10 % of the electrons are removed, then the number of removed electrons are :

$n=\dfrac{10}{100}\times 5\times 10^{21}\\\\n=5\times 10^{20}$

It means that the net charge removed on the sphere is :

q = ne

$q=-1.6\times 10^{-19}\times 5\times 10^{20}\\\\q=-80\ C$

Hence, we can say that net charge on the sphere after ejection of 10% electrons are 80 C.

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