Question

In a new system of units, the unit of mass is a kg, the units of length and time are respectively b m and



c. Find the magnitude of 6 w of power in this system?

Answer 1

L

I

K

E

A

N

D

R

A

T

E

Explanation:

THANKS , BE HAPPY

Answer 2

Concept:

The quantity of energy transferred or transformed per unit of time is known as power.

A unit of measurement is a specific magnitude of a quantity that has been established and recognised by law or convention and is used as a benchmark for measuring other quantities of the same kind.

Given:

The unit of mass is a kg, the unit of length is b meter and the unit of time is c seconds.

Find:

The magnitude of 6 watt power in the system.

Solution:

Power can be defined as the work done by an object in a particular amount of time.

Power (W) = work done in kg meter square / time

We know that,

Watt, $W=\frac{J}{sec}$

$W=\frac{N.m}{s} =\frac{kgm.s^{-2}\times m}{s}=\frac{kg.m^2}{s^3}=kg.m^2/s^{-3}$

Therefore,

$W=\frac{Kg.m^{2}}{s^{3}}$

Now,

the new units of mass, length and time are a kg, b meter, and c seconds respectively.

So,

$1 kg=\frac{1}{a}$

$1 m=\frac{1}{b}$

$1 sec=\frac{1}{c}$

The power in the system is $6W$.

$6W=6\times \frac{kg.m^2}{s^3}$

$6W=6\times \frac{\frac{1}{a}\times \frac{1}{b^2} }{\frac{1}{c^3} }$

$6W=\frac{6c^3}{ab^2}$

The magnitude of 6W of power in the system is $\frac{6c^3}{ab^2}$.

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