in a no of twodigits the sum of the digit is 7.if 27is added to the no.theno.is reversed .find the no.
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let the digit in the units place be x
their sum is 7
therefore, digit in the tens place=7-x
the number is
10(7-x)+x
=70-10x+x
=70-9x______(i)
given,
if 27 is added to the number,the digits are reversed.
therefore,
digits in units place = 7-x
digit in tens place=x
the new number is
10(x)+7-x
10x+7-x
=9x+7_____(ii)
according to the question,
70-9x+27=9x+7
97-9x=9x+7
97-7=9x+9x
90=18x
x=5
digit in units place=x=5
digit in tens place=7-x=7-5=2
the original number is 25
their sum is 7
therefore, digit in the tens place=7-x
the number is
10(7-x)+x
=70-10x+x
=70-9x______(i)
given,
if 27 is added to the number,the digits are reversed.
therefore,
digits in units place = 7-x
digit in tens place=x
the new number is
10(x)+7-x
10x+7-x
=9x+7_____(ii)
according to the question,
70-9x+27=9x+7
97-9x=9x+7
97-7=9x+9x
90=18x
x=5
digit in units place=x=5
digit in tens place=7-x=7-5=2
the original number is 25
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