Math, asked by adithyaj2910, 2 months ago


In a normal chess board, the number of ways of choosing a rectangle whose diagonals do not intersect at right angles

Answers

Answered by Anonymous
11

Step-by-step explanation:

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Description

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Answered by jewelannebasit
0

Answer:

Hope this helps...

Step-by-step explanation:

There are 64 squares on the chess board.

Two squares can be selected out of 64 in

64

C

2

ways.

Now to select squares such that they have a common side is as follows

in each row, there are 7 possible pairs of adjacent squares.

Therefore there are 7×8=56 pairs of horizontally adjacent squares.

Similarly, in each column, there are 7 possible pairs of adjacent squares.

There are 7×8=56 pairs of vertically adjacent squares.

Hence, there are total 56+56=112 pairs of adjacent squares.

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